1,92x^2-4,17x+1,13=0

Solution for 1,92x^2-4,17x+1,13=0 equation:

1.92x^2-4.17x+1.13=0

a = 1.92; b = -4.17; c = +1.13;
Δ = b2-4ac
Δ = -4.172-4·1.92·1.13
Δ = 8.7105
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.17)-\sqrt{8.7105}}{2*1.92}=\frac{4.17-\sqrt{8.7105}}{3.84}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.17)+\sqrt{8.7105}}{2*1.92}=\frac{4.17+\sqrt{8.7105}}{3.84}
$